To apply 4 pounds of actual nitrogen per 1,000 square feet using 20-10-5 fertilizer, how many pounds of fertilizer are required?

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Prepare for the CR-21 Landscapes and Irrigation Test. Utilize flashcards and multiple-choice questions featuring hints and explanations. Get exam-ready!

Multiple Choice

To apply 4 pounds of actual nitrogen per 1,000 square feet using 20-10-5 fertilizer, how many pounds of fertilizer are required?

Explanation:
The fertilizer’s nitrogen content is the key. A 20-10-5 mix means 20% of the weight is nitrogen. So each pound of fertilizer provides 0.20 pounds of actual N. To deliver 4 pounds of N per 1,000 square feet, you solve 0.20 × (pounds of fertilizer) = 4, which gives pounds of fertilizer = 4 ÷ 0.20 = 20. So 20 pounds of fertilizer are needed. Quick check: 20 pounds × 0.20 = 4 pounds of N. The other numbers (10 and 5) are phosphorus and potassium and don’t affect this calculation.

The fertilizer’s nitrogen content is the key. A 20-10-5 mix means 20% of the weight is nitrogen. So each pound of fertilizer provides 0.20 pounds of actual N. To deliver 4 pounds of N per 1,000 square feet, you solve 0.20 × (pounds of fertilizer) = 4, which gives pounds of fertilizer = 4 ÷ 0.20 = 20. So 20 pounds of fertilizer are needed. Quick check: 20 pounds × 0.20 = 4 pounds of N. The other numbers (10 and 5) are phosphorus and potassium and don’t affect this calculation.

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